Estimating Pi
The fact that π exists is due to the similarity of all circles. The ratio of the circumference to the diameter would not be constant otherwise.
The simple idea of similarity is commonly being reported as overly hard on children. I am confident that the problem must lie with the manner of presentation and not with the similarity per se. This is because children grow up in the world of models: toy cars, stuffed animals, house drawings, etc. To detect pattern - an activity in which the human brain has no peer - is to see similarities. This is to say that the notion of similarity should not be too difficult for the kids, i.e., if it is introduced properly. The difficulty usually lies in the algebraic expression of similarity not in the geometric concept.
I was very pleasantly surprised by a submission to the latest Math teachers at play carnival that featured a gentle introduction into the concept of similarity. Once explained and internalized, the concept was applied to the determination of π.
Here I would like to add my 2¢. It is a common practice to measure and tabulate the diameter and the circumference of several round objects and take the ratio. "Lo and behold" goes the argument, "the results are so close that not only may we estimate π but also convince ourselves that this fellow really exists."
Such experimentation goes a long way as a verification of an abstract concept of the similarity of all circles. However, we can easily do much better in estimating the value of π.
Let D and C be a measurement of the radius and of the circumference of a circular object with D0 and C0 being the real (but unknown) values. We assume that D is close to D0 and C is close to C0 and hope further that the ratio C/D is close to C0D0.
The accuracy of the measurement, i.e., the estimate for |C0 - C| depends only on the measuring device. For example, if a ruler is used then the maximum error between the "real" and measured values may be assumed to be one half of the smallest division marked on the ruler. This is true for "big" and "small" lengths. If that max error is denoted Δ then |C0 - C| < Δ, for any circumference C.
How do we measure circumference? Simple: take a thread and wrap it once around the object, unwrap it, keep it stretched and measure the length of the thread. Obviously, if we wrap the thread several times over then the measurements will have to be divided by the number of turns the thread was wrapped around the object. If n is the number of turn then the the measured length is close to nC. How close? The estimate is still within the same precision marks as it was for a single turn, i.e., Δ. For an estimate C0 we then have
Let's see how it works. For a round object I took a carton tube, a leftover from a roll of paper towels:
I wrapped a thread around the tube several times and made the marks:
The diameter was measured to be D = 13/8. (All measurements are in inches.) Then I tabulated the results for 1, 2, 3, and 4 wraps of the thread:
| 1 | 2 | 3 | 4 | ||
|---|---|---|---|---|---|
| nC | 43/8 | 21/2 | 31/2 | 41/2 | |
| nC/nD | 3.3077 | 3.2308 | 3.1795 | 3.1538 |
(The numbers in the bottom row have been rounded to 4 digits.)
I did not have a long enough ruler to measure 5 or more turns but the trend could be easily observed with just four measurements: the ratios go closer to π as the number of turns of the thread around the object grows.
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Couldn't seem to comment on the prior 'carnival' post for some reason(???) so will note it here:
July 14th, 2010 at 1:02 pmThanks for inclusion in what looks likes a wonderful carnival edition, but 1 correction: last time I checked the pertinent body parts, "Shecky Riemann" (ME!), was still a he, not a she
Shecky, I am sorry. Hopefully, I fixed all the mishaps.
I am certain, if I saw a picture I would not have second thoughts.
July 14th, 2010 at 1:13 pmI wonder if you have suggestions for accurate measurement of the diameter, which is also not trivial for children to measure, due to the need to figure out where the largest chord is.
July 23rd, 2010 at 3:01 amHi mathmom,
finding the diameter of a circle can be done by paperfolding. The simplest way is to place the circular object at the edge of a rectangular piece of paper. In this position the circle should appear just touching the edge from inside the rectangle. Next bend the opposite edge of the paper so as to touch the circle from the "other end". This requires that your fold be perpendicular to the remaining sides of the rectangle. Just slide the paper along those sides. When the fold is completed, you have a piece of paper divided into two rectangular parts, with two pairs of equal sides. The difference between the other sides is the diameter of the circle.
I would let several kids measure the same object, as described, and then calculate the average.
July 23rd, 2010 at 6:59 amThanks, that does sound like a good way.
July 23rd, 2010 at 10:18 am